总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×1.13)*(√30)×0.00252×195)+0.75×10^(-3)×280×(1608+509)×0.707 的值.
题型:数学计算
解:
1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×1.13)*(√30)×0.00252×195)+0.75×10^(-3)×280×(1608+509)×0.707
=1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×1.13)*(√30)×0.00252×195)+0.75×10^(-3)×280×(1608+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√(2.678*(√30)×0.00252×195)+0.75×10^(-3)×280×(1608+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√(2.678*5.477226×0.00252×195)+0.75×10^(-3)×280×(1608+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√7.207785+0.75×10^(-3)×280×(1608+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√7.207785+0.75×10^(-3)×280×(1608+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√7.207785+0.75×10^-3×280×2117×0.707
=1×1×1.1×0.45×10^-3×200×1449*2.684732+0.75×10^-3×280×2117×0.707
=1×1×1.1×0.45×0.001×200×1449*2.684732+0.75×10^(-3)×280×2117×0.707
=1×1×1.1×0.45×0.001×200×1449*2.684732+0.75×0.001×280×2117×0.707
=1×1.1×0.45×0.001×200×1449*2.684732+0.75×0.001×280×2117×0.707
=1.1×0.45×0.001×200×1449*2.684732+0.75×0.001×280×2117×0.707
=0.495×0.001×200×1449*2.684732+0.75×0.001×280×2117×0.707
=0.000495×200×1449*2.684732+0.75×0.001×280×2117×0.707
=0.099×1449*2.684732+0.75×0.001×280×2117×0.707
=143.451*2.684732+0.75×0.001×280×2117×0.707
=385.12749+0.75×0.001×280×2117×0.707
=385.12749+0.00075×280×2117×0.707
=385.12749+0.21×2117×0.707
=385.12749+444.57×0.707
=385.12749+314.31099
=699.43848 答案:1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×1.13)*(√30)×0.00252×195)+0.75×10^(-3)×280×(1608+509)×0.707=699.43848你的问题在这里没有得到解决?请到 热门难题 里面看看吧!