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〖1/1算式〗
作业:求算式 ln((e^(1/9.0715)+e^(1/10.07945)+e^(1/11.08739))/((0.0279-0.00321)/0.00374)) 的值.
题型:数学计算
解:
ln((e^(1/9.0715)+e^(1/10.07945)+e^(1/11.08739))/((0.0279-0.00321)/0.00374))
=ln((e^0.110235+e^(1/10.07945)+e^(1/11.08739))/((0.0279-0.00321)/0.00374))
=ln((e^0.110235+e^0.099212+e^(1/11.08739))/((0.0279-0.00321)/0.00374))
=ln((e^0.110235+e^0.099212+e^0.090193)/((0.0279-0.00321)/0.00374))
=ln(3.315226/((0.0279-0.00321)/0.00374))
=ln(3.315226/(0.02469/0.00374))
=ln(3.315226/6.601604)
=ln0.502185
=-0.688787 答案:ln((e^(1/9.0715)+e^(1/10.07945)+e^(1/11.08739))/((0.0279-0.00321)/0.00374))=-0.688787你的问题在这里没有得到解决?请到 热门难题 里面看看吧!