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〖1/1算式〗
作业:求算式 -4000-1000/(1+1.01)+600*(1-(1+1.01)^29)/(1-1.01)*(1+1.01)^2 的值.
题型:数学计算
解:
-4000-1000/(1+1.01)+600*(1-(1+1.01)^29)/(1-1.01)*(1+1.01)^2
=-4000-1000/2.01+600*(1-(1+1.01)^29)/(1-1.01)*(1+1.01)^2
=-4000-1000/2.01+600*(1-2.01^29)/(1-1.01)*(1+1.01)^2
=-4000-1000/2.01+600*(-620419821.587958)/(1-1.01)*(1+1.01)^2
=-4000-1000/2.01+600*(-620419821.587958)/(-0.01)*(1+1.01)^2
=-4000-1000/2.01+600*(-620419821.587958)/(-0.01)*2.01^2
=-4000-1000/2.01+600*(-620419821.587958)/(-0.01)*4.040099999999999
=-4000-497.512438+600*(-620419821.587958)/(-0.01)*4.040099999999999
=-4000-497.512438+(-372251892952.77478)/(-0.01)*4.040099999999999
=-4000-497.512438+37225189295277.476562*4.040099999999999
=-4000-497.512438+150393487271850.5
=-4497.512438+150393487271850.5
=150393487267353 答案:-4000-1000/(1+1.01)+600*(1-(1+1.01)^29)/(1-1.01)*(1+1.01)^2=150393487267353你的问题在这里没有得到解决?请到 热门难题 里面看看吧!