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〖1/1算式〗
作业:求算式 ((tan10+tan24.9)/(1-tan10*tan24.9)-1/tan24.9)/((tan18.3+tan(24.9*1.83))/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83)) 的值.
题型:数学计算
解:
((tan10+tan24.9)/(1-tan10*tan24.9)-1/tan24.9)/((tan18.3+tan(24.9*1.83))/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83))
=(0.411324/(1-tan10*tan24.9)-1/tan24.9)/((tan18.3+tan(24.9*1.83))/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83))
=(0.411324/1.153686-1/tan24.9)/((tan18.3+tan(24.9*1.83))/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83))
=4.575281/((tan18.3+tan(24.9*1.83))/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83))
=4.575281/((tan18.3+tan45.567)/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83))
=4.575281/((-72.516559)/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83))
=4.575281/(-72.516559/(1-tan18.3*tan45.567)-1/tan(24.9*1.83))
=4.575281/(-72.516559/(-43.040808)-1/tan(24.9*1.83))
=4.575281/(-72.516559/(-43.040808)-1/tan45.567)
=4.575281/1.69874
=2.693338 答案:((tan10+tan24.9)/(1-tan10*tan24.9)-1/tan24.9)/((tan18.3+tan(24.9*1.83))/(1-tan18.3*tan(24.9*1.83))-1/tan(24.9*1.83))=2.693338 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!