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〖1/1算式〗
作业:求算式 tan(65.63)/((-1/44.79)*((0.5*tan10+tan27.95)/(1-0.5*tan10*tan27.95)-1/tan27.95)*(1/2)) 的值.
题型:数学计算
解:
tan(65.63)/((-1/44.79)*((0.5*tan10+tan27.95)/(1-0.5*tan10*tan27.95)-1/tan27.95)*(1/2))
=tan65.63/((-1/44.79)*((0.5*tan10+tan27.95)/(1-0.5*tan10*tan27.95)-1/tan27.95)*(1/2))
=tan65.63/((-0.022326)*((0.5*tan10+tan27.95)/(1-0.5*tan10*tan27.95)-1/tan27.95)*(1/2))
=tan65.63/(-0.022326*((-0.012026)/(1-0.5*tan10*tan27.95)-1/tan27.95)*(1/2))
=tan65.63/(-0.022326*(-0.012026/1.108991-1/tan27.95)*(1/2))
=tan65.63/(-0.022326*2.963523*(1/2))
=tan65.63/(-0.022326*2.963523*0.5)
=tan65.63/(-0.033082)
=-0.357619/-0.033082
=10.810078 答案:tan(65.63)/((-1/44.79)*((0.5*tan10+tan27.95)/(1-0.5*tan10*tan27.95)-1/tan27.95)*(1/2))=10.810078 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!