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〖1/1算式〗
作业:求算式 tan(70.34)/((-1/61.31)*((0.5*tan10+tan29.57)/(1-0.5*tan10*tan29.57)-1/tan29.57)*(1/2)) 的值.
题型:数学计算
解:
tan(70.34)/((-1/61.31)*((0.5*tan10+tan29.57)/(1-0.5*tan10*tan29.57)-1/tan29.57)*(1/2))
=tan70.34/((-1/61.31)*((0.5*tan10+tan29.57)/(1-0.5*tan10*tan29.57)-1/tan29.57)*(1/2))
=tan70.34/((-0.016311)*((0.5*tan10+tan29.57)/(1-0.5*tan10*tan29.57)-1/tan29.57)*(1/2))
=tan70.34/(-0.016311*(3.866646/(1-0.5*tan10*tan29.57)-1/tan29.57)*(1/2))
=tan70.34/(-0.016311*(3.866646/(-0.148397)-1/tan29.57)*(1/2))
=tan70.34/(-0.016311*(-26.338382)*(1/2))
=tan70.34/(-0.016311*(-26.338382)*0.5)
=tan70.34/0.214803
=2.775347/0.214803
=12.920429 答案:tan(70.34)/((-1/61.31)*((0.5*tan10+tan29.57)/(1-0.5*tan10*tan29.57)-1/tan29.57)*(1/2))=12.920429 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!