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〖1/1算式〗
作业:求算式 ((0.1*16.3078*1.0574)/(1+0.1*1.0574))*((100-0.0999-0.0021)/100)*(1/(1+0.31*0.0021))+(2.24/1.31) 的值.
题型:数学计算
解:
((0.1*16.3078*1.0574)/(1+0.1*1.0574))*((100-0.0999-0.0021)/100)*(1/(1+0.31*0.0021))+(2.24/1.31)
=(1.724387/(1+0.1*1.0574))*((100-0.0999-0.0021)/100)*(1/(1+0.31*0.0021))+(2.24/1.31)
=(1.724387/1.10574)*((100-0.0999-0.0021)/100)*(1/(1+0.31*0.0021))+(2.24/1.31)
=1.559487*((100-0.0999-0.0021)/100)*(1/(1+0.31*0.0021))+(2.24/1.31)
=1.559487*(99.898/100)*(1/(1+0.31*0.0021))+(2.24/1.31)
=1.559487*0.99898*(1/(1+0.31*0.0021))+(2.24/1.31)
=1.559487*0.99898*(1/1.000651)+(2.24/1.31)
=1.559487*0.99898*0.999349+(2.24/1.31)
=1.559487*0.99898*0.999349+1.709924
=1.557896*0.999349+1.709924
=1.556882+1.709924
=3.266806 答案:((0.1*16.3078*1.0574)/(1+0.1*1.0574))*((100-0.0999-0.0021)/100)*(1/(1+0.31*0.0021))+(2.24/1.31)=3.266806你的问题在这里没有得到解决?请到 热门难题 里面看看吧!