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〖1/1算式〗
作业:求算式 ((0.1*16.3078*1.0574)/(1+0.1*1.0574))*((100-9.99-0.21)/100)*(1/(1+0.31*0.21))+(2.24/1.31) 的值.
题型:数学计算
解:
((0.1*16.3078*1.0574)/(1+0.1*1.0574))*((100-9.99-0.21)/100)*(1/(1+0.31*0.21))+(2.24/1.31)
=(1.724387/(1+0.1*1.0574))*((100-9.99-0.21)/100)*(1/(1+0.31*0.21))+(2.24/1.31)
=(1.724387/1.10574)*((100-9.99-0.21)/100)*(1/(1+0.31*0.21))+(2.24/1.31)
=1.559487*((100-9.99-0.21)/100)*(1/(1+0.31*0.21))+(2.24/1.31)
=1.559487*(89.8/100)*(1/(1+0.31*0.21))+(2.24/1.31)
=1.559487*0.898*(1/(1+0.31*0.21))+(2.24/1.31)
=1.559487*0.898*(1/1.0651)+(2.24/1.31)
=1.559487*0.898*0.938879+(2.24/1.31)
=1.559487*0.898*0.938879+1.709924
=1.400419*0.938879+1.709924
=1.314824+1.709924
=3.024748 答案:((0.1*16.3078*1.0574)/(1+0.1*1.0574))*((100-9.99-0.21)/100)*(1/(1+0.31*0.21))+(2.24/1.31)=3.024748你的问题在这里没有得到解决?请到 热门难题 里面看看吧!