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〖1/1算式〗
作业:求算式 0.1*log(0.1/0.4)+0.2*log(0.2/0.3)+0.3*log(0.3/0.2)+0.4*log(0.4/0.1) 的值.
题型:数学计算
解:
0.1*log(0.1/0.4)+0.2*log(0.2/0.3)+0.3*log(0.3/0.2)+0.4*log(0.4/0.1)
=0.1*(-1.386294)+0.2*log(0.2/0.3)+0.3*log(0.3/0.2)+0.4*log(0.4/0.1)
=0.1*(-1.386294)+0.2*(-0.405465)+0.3*log(0.3/0.2)+0.4*log(0.4/0.1)
=0.1*(-1.386294)+0.2*(-0.405465)+0.3*0.405465+0.4*log(0.4/0.1)
=0.1*(-1.386294)+0.2*(-0.405465)+0.3*0.405465+0.4*1.386294
=-0.138629+0.2*(-0.405465)+0.3*0.405465+0.4*1.386294
=-0.138629+(-0.081093)+0.3*0.405465+0.4*1.386294
=-0.138629+-0.081093+0.121639+0.4*1.386294
=-0.138629+-0.081093+0.121639+0.554518
=-0.219722+0.121639+0.554518
=-0.098083+0.554518
=0.456435 答案:0.1*log(0.1/0.4)+0.2*log(0.2/0.3)+0.3*log(0.3/0.2)+0.4*log(0.4/0.1)=0.456435你的问题在这里没有得到解决?请到 热门难题 里面看看吧!