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〖1/1算式〗
作业:求算式 (20/3)*7089*(1349.352-269.835)^2+(1/3)*1850*269.835^3-(1/3)*1670*(269.835-130)^3 的值.
题型:数学计算
解:
(20/3)*7089*(1349.352-269.835)^2+(1/3)*1850*269.835^3-(1/3)*1670*(269.835-130)^3
=6.666667*7089*(1349.352-269.835)^2+(1/3)*1850*269.835^3-(1/3)*1670*(269.835-130)^3
=6.666667*7089*1079.517^2+(1/3)*1850*269.835^3-(1/3)*1670*(269.835-130)^3
=6.666667*7089*1079.517^2+0.333333*1850*269.835^3-(1/3)*1670*(269.835-130)^3
=6.666667*7089*1079.517^2+0.333333*1850*269.835^3-0.333333*1670*(269.835-130)^3
=6.666667*7089*1079.517^2+0.333333*1850*269.835^3-0.333333*1670*139.835^3
=6.666667*7089*1165356.953289000084624+0.333333*1850*269.835^3-0.333333*1670*139.835^3
=6.666667*7089*1165356.953289000084624+0.333333*1850*19646936.547757871448994-0.333333*1670*139.835^3
=6.666667*7089*1165356.953289000084624+0.333333*1850*19646936.547757871448994-0.333333*1670*2734309.430007875431329
=47260.002363*1165356.953289000084624+0.333333*1850*19646936.547757871448994-0.333333*1670*2734309.430007875431329
=55074772366.17662+0.333333*1850*19646936.547757871448994-0.333333*1670*2734309.430007875431329
=55074772366.17662+616.66605*19646936.547757871448994-0.333333*1670*2734309.430007875431329
=55074772366.17662+12115598755.506483-0.333333*1670*2734309.430007875431329
=55074772366.17662+12115598755.506483-556.66611*2734309.430007875431329
=55074772366.17662+12115598755.506483-1522097393.938801
=67190371121.683105-1522097393.938801
=65668273727.744301 答案:(20/3)*7089*(1349.352-269.835)^2+(1/3)*1850*269.835^3-(1/3)*1670*(269.835-130)^3=65668273727.744301你的问题在这里没有得到解决?请到 热门难题 里面看看吧!