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〖1/1算式〗
作业:求算式 4018.25+34.05*2+(1.7^2*π*16*2.5/4+1.7*1.7*17*0.732/4)-5.34*(20*2.5+70*0.732)/2 的值.
题型:数学计算
解:
4018.25+34.05*2+(1.7^2*π*16*2.5/4+1.7*1.7*17*0.732/4)-5.34*(20*2.5+70*0.732)/2
=4018.25+34.05*2+99.78282-5.34*(20*2.5+70*0.732)/2
=4018.25+34.05*2+99.78282-5.34*101.24/2
=4018.25+68.1+99.78282-5.34*101.24/2
=4018.25+68.1+99.78282-540.6216/2
=4018.25+68.1+99.78282-270.3108
=4086.35+99.78282-270.3108
=4186.13282-270.3108
=3915.82202 答案:4018.25+34.05*2+(1.7^2*π*16*2.5/4+1.7*1.7*17*0.732/4)-5.34*(20*2.5+70*0.732)/2=3915.82202你的问题在这里没有得到解决?请到 热门难题 里面看看吧!