本次共计算 1 个题目:每一题对 x 求 1 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数sqrt((\frac{sin(abs + x)}{(x - ln({x}^{e^{π}}))})) 关于 x 的 1 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = sqrt(\frac{sin(abs + x)}{(x - ln({x}^{e^{π}}))})\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( sqrt(\frac{sin(abs + x)}{(x - ln({x}^{e^{π}}))})\right)}{dx}\\=&\frac{((\frac{-(1 - \frac{({x}^{e^{π}}((e^{π}*0)ln(x) + \frac{(e^{π})(1)}{(x)}))}{({x}^{e^{π}})})}{(x - ln({x}^{e^{π}}))^{2}})sin(abs + x) + \frac{cos(abs + x)(0 + 1)}{(x - ln({x}^{e^{π}}))})*\frac{1}{2}}{(\frac{sin(abs + x)}{(x - ln({x}^{e^{π}}))})^{\frac{1}{2}}}\\=&\frac{e^{π}sin^{\frac{1}{2}}(abs + x)}{2(x - ln({x}^{e^{π}}))^{\frac{3}{2}}x} + \frac{cos(abs + x)}{2(x - ln({x}^{e^{π}}))^{\frac{1}{2}}sin^{\frac{1}{2}}(abs + x)} - \frac{sin^{\frac{1}{2}}(abs + x)}{2(x - ln({x}^{e^{π}}))^{\frac{3}{2}}}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!