本次共计算 1 个题目:每一题对 x 求 1 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数4{x}^{(\frac{(π - 1)(1 - sin(π)x)}{(π + 1)})} 关于 x 的 1 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = 4{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( 4{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}\right)}{dx}\\=&4({x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}((-(\frac{-(0 + 0)}{(π + 1)^{2}})πxsin(π) - \frac{πsin(π)}{(π + 1)} - \frac{πxcos(π)*0}{(π + 1)} + (\frac{-(0 + 0)}{(π + 1)^{2}})π + 0 + (\frac{-(0 + 0)}{(π + 1)^{2}})xsin(π) + \frac{sin(π)}{(π + 1)} + \frac{xcos(π)*0}{(π + 1)} - (\frac{-(0 + 0)}{(π + 1)^{2}}))ln(x) + \frac{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})(1)}{(x)}))\\=& - \frac{4π{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}ln(x)sin(π)}{(π + 1)} + \frac{4{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}ln(x)sin(π)}{(π + 1)} - \frac{4π{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}sin(π)}{(π + 1)} + \frac{4π{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}}{(π + 1)x} + \frac{4{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}sin(π)}{(π + 1)} - \frac{4{x}^{(\frac{-πxsin(π)}{(π + 1)} + \frac{π}{(π + 1)} + \frac{xsin(π)}{(π + 1)} - \frac{1}{(π + 1)})}}{(π + 1)x}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!