数学
         
语言:中文    Language:English
求导函数:
    输入一个原函数(即需要求导的函数),然后设置需要求导的变量和求导的阶数,点击“下一步”按钮,即可获得该函数相应阶数的导函数。
    注意,输入的函数支持数学函数和其它常量。
    当前位置:求导函数 > 导函数计算历史 > 答案

    本次共计算 1 个题目:每一题对 d 求 1 阶导数。
    注意,变量是区分大小写的。
\[ \begin{equation}\begin{split}【1/1】求函数\frac{csqrt(\frac{1}{(2lln(\frac{b}{a})(\frac{1}{d} + \frac{4ln(\frac{(esqrt(({b}^{2} - {a}^{2}) + {(l + d)}^{2}))}{(2d)})}{(pia)}))})}{(api)} 关于 d 的 1 阶导数:\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = \frac{csqrt(\frac{1}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})})}{api}\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( \frac{csqrt(\frac{1}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})})}{api}\right)}{dd}\\=&\frac{c(\frac{-(\frac{2l*-ln(\frac{b}{a})}{d^{2}} + \frac{2l*0}{d(\frac{b}{a})} + \frac{8l*0ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api(\frac{b}{a})} + \frac{8lln(\frac{b}{a})(\frac{\frac{1}{2}*-esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d^{2}} + \frac{\frac{1}{2}*0sqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d} + \frac{\frac{1}{2}e(0 + 0 + 2l + 0 + 2d)*\frac{1}{2}}{d(b^{2} - a^{2} + 2ld + l^{2} + d^{2})^{\frac{1}{2}}})}{api(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})})}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})^{2}})*\frac{1}{2}}{api(\frac{1}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})})^{\frac{1}{2}}}\\=&\frac{clln(\frac{b}{a})}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})^{\frac{3}{2}}apid^{2}} + \frac{4clln(\frac{b}{a})}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})^{\frac{3}{2}}a^{2}p^{2}i^{2}d} - \frac{4cl^{2}ln(\frac{b}{a})}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})^{\frac{3}{2}}(b^{2} - a^{2} + 2ld + l^{2} + d^{2})^{\frac{1}{2}}a^{2}p^{2}i^{2}sqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})} - \frac{4cldln(\frac{b}{a})}{(\frac{2lln(\frac{b}{a})}{d} + \frac{8lln(\frac{b}{a})ln(\frac{\frac{1}{2}esqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}{d})}{api})^{\frac{3}{2}}(b^{2} - a^{2} + 2ld + l^{2} + d^{2})^{\frac{1}{2}}a^{2}p^{2}i^{2}sqrt(b^{2} - a^{2} + 2ld + l^{2} + d^{2})}\\ \end{split}\end{equation} \]



你的问题在这里没有得到解决?请到 热门难题 里面看看吧!





  新增加学习笔记(安卓版)百度网盘快速下载应用程序,欢迎使用。
  新增加学习笔记(安卓版)本站下载应用程序,欢迎使用。

  新增线性代数行列式的计算,欢迎使用。

  数学计算和一元方程已经支持正割函数余割函数,欢迎使用。

  新增加贷款计算器模块(具体位置:数学运算 > 贷款计算器),欢迎使用。