求导函数：
输入一个原函数（即需要求导的函数），然后设置需要求导的变量和求导的阶数，点击“下一步”按钮，即可获得该函数相应阶数的导函数。
注意，输入的函数支持数学函数和其它常量。
输入一个原函数（即需要求导的函数），然后设置需要求导的变量和求导的阶数，点击“下一步”按钮，即可获得该函数相应阶数的导函数。
注意，输入的函数支持数学函数和其它常量。
本次共计算 1 个题目：每一题对 x 求 1 阶导数。
注意，变量是区分大小写的。
\[ \begin{equation}\begin{split}【1/1】求函数-arctan(\frac{((2{A}^{2}C){\frac{1}{B}}^{2} - \frac{(4{A}^{3}C{sin(x)}^{2})}{({A}^{2}{cos(x)}^{2} - {B}^{2})})}{(ACDtan(x) + \frac{(2ADcos(x)sin(x))}{({A}^{2}{cos(x)}^{2} - B)})}) 关于 x 的 1 阶导数：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = -arctan(\frac{2A^{2}C}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})B^{2}} - \frac{4A^{3}Csin^{2}(x)}{(A^{2}cos^{2}(x) - B^{2})(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})})\\&\color{blue}{函数的第 1 阶导数：}\\&\frac{d\left( -arctan(\frac{2A^{2}C}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})B^{2}} - \frac{4A^{3}Csin^{2}(x)}{(A^{2}cos^{2}(x) - B^{2})(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})})\right)}{dx}\\=&-(\frac{(\frac{2(\frac{-(ACDsec^{2}(x)(1) + 2(\frac{-(A^{2}*-2cos(x)sin(x) + 0)}{(A^{2}cos^{2}(x) - B)^{2}})ADsin(x)cos(x) + \frac{2ADcos(x)cos(x)}{(A^{2}cos^{2}(x) - B)} + \frac{2ADsin(x)*-sin(x)}{(A^{2}cos^{2}(x) - B)})}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}})A^{2}C}{B^{2}} + 0 - \frac{4(\frac{-(A^{2}*-2cos(x)sin(x) + 0)}{(A^{2}cos^{2}(x) - B^{2})^{2}})A^{3}Csin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})} - \frac{4(\frac{-(ACDsec^{2}(x)(1) + 2(\frac{-(A^{2}*-2cos(x)sin(x) + 0)}{(A^{2}cos^{2}(x) - B)^{2}})ADsin(x)cos(x) + \frac{2ADcos(x)cos(x)}{(A^{2}cos^{2}(x) - B)} + \frac{2ADsin(x)*-sin(x)}{(A^{2}cos^{2}(x) - B)})}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}})A^{3}Csin^{2}(x)}{(A^{2}cos^{2}(x) - B^{2})} - \frac{4A^{3}C*2sin(x)cos(x)}{(A^{2}cos^{2}(x) - B^{2})(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})})}{(1 + (\frac{2A^{2}C}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})B^{2}} - \frac{4A^{3}Csin^{2}(x)}{(A^{2}cos^{2}(x) - B^{2})(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})})^{2})})\\=&\frac{2A^{3}C^{2}Dsec^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)B^{2}} + \frac{8A^{5}CDsin^{2}(x)cos^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B)^{2}(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)B^{2}} + \frac{4A^{3}CDcos^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B)(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)B^{2}} - \frac{4A^{3}CDsin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B)(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)B^{2}} + \frac{8A^{5}Csin^{3}(x)cos(x)}{(A^{2}cos^{2}(x) - B^{2})^{2}(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)} - \frac{4A^{4}C^{2}Dsin^{2}(x)sec^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)} - \frac{16A^{6}CDsin^{4}(x)cos^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})(A^{2}cos^{2}(x) - B)^{2}(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)} - \frac{8A^{4}CDsin^{2}(x)cos^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})(A^{2}cos^{2}(x) - B)(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)} + \frac{8A^{4}CDsin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})(A^{2}cos^{2}(x) - B)(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)} + \frac{8A^{3}Csin(x)cos(x)}{(A^{2}cos^{2}(x) - B^{2})(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})(\frac{4A^{4}C^{2}}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}B^{4}} - \frac{16A^{5}C^{2}sin^{2}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})B^{2}} + \frac{16A^{6}C^{2}sin^{4}(x)}{(ACDtan(x) + \frac{2ADsin(x)cos(x)}{(A^{2}cos^{2}(x) - B)})^{2}(A^{2}cos^{2}(x) - B^{2})^{2}} + 1)}\\ \end{split}\end{equation} \]
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