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作业:求算式 40*((0.04*(1.02^(-5))-0.5+0.5*(1.02^(-4)))/0.0004)-2000*(1.02^(-5)) 的值.
题型:数学计算
解:
40*((0.04*(1.02^(-5))-0.5+0.5*(1.02^(-4)))/0.0004)-2000*(1.02^(-5))
=40*((0.04*(1.02^(-5))-0.5+0.5*(1.02^(-4)))/0.0004)-2000*(1.02^(-5))
=40*((0.04*0.905730809829916-0.5+0.5*(1.02^(-4)))/0.0004)-2000*(1.02^(-5))
=40*((0.04*0.905730809829916-0.5+0.5*(1.02^(-4)))/0.0004)-2000*(1.02^(-5))
=40*((0.04*0.905730809829916-0.5+0.5*0.923845426026514)/0.0004)-2000*(1.02^(-5))
=40*((-0.001848)/0.0004)-2000*(1.02^(-5))
=40*(-4.62)-2000*(1.02^(-5))
=40*(-4.62)-2000*(1.02^(-5))
=40*(-4.62)-2000*0.905730809829916
=-184.8-2000*0.905730809829916
=-184.8-1811.46162
=-1996.26162 答案:40*((0.04*(1.02^(-5))-0.5+0.5*(1.02^(-4)))/0.0004)-2000*(1.02^(-5))=-1996.26162你的问题在这里没有得到解决?请到 热门难题 里面看看吧!