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〖1/1算式〗
作业:求算式 (25/(1484.51*21))+(0.000176*25/21)+(0.000051*25/23)+0.00009+(1/7025.36) 的值.
题型:数学计算
解:
(25/(1484.51*21))+(0.000176*25/21)+(0.000051*25/23)+0.00009+(1/7025.36)
=(25/31174.71)+(0.000176*25/21)+(0.000051*25/23)+0.00009+(1/7025.36)
=0.000802+(0.000176*25/21)+(0.000051*25/23)+0.00009+(1/7025.36)
=0.000802+0.00021+(0.000051*25/23)+0.00009+(1/7025.36)
=0.000802+0.00021+0.000055+0.00009+(1/7025.36)
=0.000802+0.00021+0.000055+0.00009+0.000142
=0.001012+0.000055+0.00009+0.000142
=0.001067+0.00009+0.000142
=0.001157+0.000142
=0.001299 答案:(25/(1484.51*21))+(0.000176*25/21)+(0.000051*25/23)+0.00009+(1/7025.36)=0.001299你的问题在这里没有得到解决?请到 热门难题 里面看看吧!