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总述:本次共解1题。其中
☆方程1题
〖 1/1方程〗
作业:求方程 (1+2d)^(2) = 0 的解.
题型:方程
解:
方程化为一般式后,用因式分解法化为:
( 2d + 1 )( 2d + 1 )=0
由
2d + 1 = 0
2d + 1 = 0
得:
有 2个解。
解一元二次方程的详细方法请参阅:《一元二次方程的解法》
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#0 /www/wwwroot/MyWeb/baidu/baidu_20250905/work/jfc_ck/bds/index.php(44): mysqli->query()
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