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总述:本次共解1题。其中
☆不等式1题
〖 1/1不等式〗
作业:求不等式 x-1 题型:不等式
解:
该不等式可以化为1个不等式:
x - 1 < ln ( x + 1 ) (1)
由ln的定义域得
x + 1 > 0 (2 )
由不等式(1)得:
-0.841406 < x < 2.146193
由不等式(2)得:
x > -1
由不等式(1)和(2)得
-0.841406 < x < 2.146193 (3)
最终答案为:
-0.841406 < x < 2.146193
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Stack trace:
#0 /www/wwwroot/MyWeb/baidu/baidu_20250905/work/jfc_ck/bds/index.php(44): mysqli->query()
#1 /www/wwwroot/MyWeb/baidu/baidu_20250905/res/work.php(48): require('...')
#2 /www/wwwroot/MyWeb/baidu/baidu_20250905/front.php(113): require('...')
#3 {main}
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