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current location:Solving equations online > On line Solution of Monovariate Equation > The history of univariate equation calculation
    √(16^2÷w^2÷(w^2+1)÷((0.01^2)*w^2+1))=-6.425
    -90-arctan(w)-arctan(0.01*w)=-180
    -π÷2-arctan(w)-arctan(0.01*w)=-π
    -90-arctan(w)-arctan(0.01*w)=-π
    √(16^2÷w^2÷(w^2+1)÷((0.01^2)*w^2+1))=1
    √(16^2÷w^2÷(w^2+1)÷((0.01^2)*w^2+1))
    X-X*5%=4292100
    2.5=230-30*s-s^2/45
    2.5=230-30s-s^2/45
    84.1 = 35.669ln(x) - 5.1569
    50 = 35.669ln(x) - 5.1569
    84.1 = 34.979ln(x) - 6.4857
    50 = 34.979ln(x) - 6.4857
    1/2=(85-a)/(a-71)
    1-(2094400/x)=0.0116
    1-x=0.0116
     3p-3p² = 9/16
    -90-arctan(w)-arctan(0.01*w)
    3p-3p²=9/16
    p-p²

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