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==equ==
Unary equation
Multivariate equation
==cal==
Solution inequality
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==LiAl==
Determinant
Matrix multiplication
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==der==
Derivative function
==img==
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==que==
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On line Solution of Monovariate Equation
> The history of univariate equation calculation
0.3+0.3*8*(cos(x)+1)+0.3*16*(cos(2*x)+1)=1
0.5+0.5*8*(cos(x)+1)+0.5*16*(cos(2*x)+1)=1
0.3+0.3*0.5*8*(cos(x)+1)+0.3*0.5*16*(cos(2*x)+1)=1
-90-arctan(0.2*w)-arctan(0.5*w)=-120
X-X*0.065-(X+10000000)*0.0003=10000000
√(10^2÷w^2÷((0.04)*w^2+1)÷((0.25)*w^2+1))=1
√(10^2÷w^2÷((0.04)*w^2+1)÷((0.25)*w^2+1))=-6.82
X-X*0.065+(X+10000000)*0.0003=10000000
20*lg√(200^2÷w^2÷((0.01)*w^2+1))=-6.82
0.2+1.6*cos(x)+2.4*cos(2*x)=1
0.3+2.4*cos(x)+4.8*cos(2*x)=1
√(200^2÷w^2÷((0.01)*w^2+1))=1
(800+X-12168.93)*(1-25%)+5213.15 = 5634.18
20*lg√(16^2÷w^2÷(w^2+1)÷((0.01^2)*w^2+1)=-6.82
20*lg√(16^2*(1+(4.39÷3×w)^2)÷w^2÷(w^2+1)÷((0.01^2)*w^2+1)÷(1+(w÷3)^2))=-6.82
0.5+4*cos(x)+8*cos(2*x)=1
√(16^2*(1+(4.39÷3×w)^2)÷w^2÷(w^2+1)÷((0.01^2)*w^2+1)÷(1+(w÷3)^2))=1
arctan(4.39÷3*w)-90-arctan(w)-arctan(0.01*w)-arctan(1/3*w)=-π
arctan(4.39÷3*w)-90-arctan(w)-arctan(0.01*w)-arctan(1/3*w)
√(16^2÷w^2÷(w^2+1)÷((0.01^2)*w^2+1))=6.425
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