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current location:Solving equations online > On line Solution of Monovariate Equation > The history of univariate equation calculation
    0.5×lg(10^2÷0.78^2÷((0.04)*0.78^2+1)÷((0.25)*0.78^2+1))=-lga
    0.1+0.1*8*x+0.1*16*x*x=1
    lg√(10^2÷0.78^2÷((0.04)*0.78^2+1)÷((0.25)*0.78^2+1))=-lga
    0.1+0.1*8*0.5*x+0.1*16*0.5*x*x=1
    2-6x^4-10x^6=0
    (x-200)/200=-5.01%
    0.1+0.1*8*0.5*(cos(x)+1)+0.1*16*0.5*(cos(2*x)+1)=1
    0.2+0.2*8*0.2*(cos(x)+1)+0.3*16*0.2*(cos(2*x)+1)=1
    0.3+0.3*8*0.5*(cos(x)+1)+0.3*16*0.5*(cos(2*x)+1)=1
    √(10^2÷0.78^2÷((0.04)*0.78^2+1)÷((0.25)*0.78^2+1))=1÷a
    0.2+0.2*8*0.5*(cos(x)+1)+0.2*16*0.5*(cos(2*x)+1)=1
    0.2+0.2*8*(cos(x)+1)+0.2*16*(cos(2*x)+1)=1
    0.3+0.3*8*(cos(x)+1)+0.3*16*(cos(2*x)+1)=1
    0.5+0.5*8*(cos(x)+1)+0.5*16*(cos(2*x)+1)=1
    0.3+0.3*0.5*8*(cos(x)+1)+0.3*0.5*16*(cos(2*x)+1)=1
    -90-arctan(0.2*w)-arctan(0.5*w)=-120
    X-X*0.065-(X+10000000)*0.0003=10000000
    √(10^2÷w^2÷((0.04)*w^2+1)÷((0.25)*w^2+1))=1
    √(10^2÷w^2÷((0.04)*w^2+1)÷((0.25)*w^2+1))=-6.82
    X-X*0.065+(X+10000000)*0.0003=10000000

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