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current location:Solving equations online > On line Solution of Monovariate Equation > The history of univariate equation calculation
    x(√(x^2+1))(√((0.2x^2)+1))=2
    -58x=(1.3-x)^3
    10.12x^3+61.26x^2-41.04x-1130.91=0
    -58(1.3-x)=x^3
    58(1.3-x)=x^3
    1+x=2
    x^2(x^2+1)((0.2x^2)+1)=4
    10.12x^3+73.14x^2+66.96x-701.57=0
    4x^6+104x^4+x^2=400
    55.889=0.5*38.333*(x-1)^2*(1+0.01*x)
    10.12x^3+100.22x^2+218.7x-495.18=0
    58x=(1.3-x)^3
    (54000-4.368X)÷(28X)
    (54000-4.368X)/(28X)
    x/0.1=0.5*9.2*(9-x)^2*(1+0.01*(10-x))
    A-A*10%>=300000
    x=16.95161+2*(15+4.619x/1.5163)*0.02179088
    -58x=(1.3+x)^3
    8x=850/3-10/3x
    8x=3/850-10/3x

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