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Work: Calculate the value of equation 1/12×(0.34)^2×((2×2.0+2.0)*(2×106.13-(2×2.0×2.0×0.8×24)/(2.0×2.0))) .
Question type: Mathematical calculation
Solution:
1/12×(0.34)^2×((2×2.0+2.0)*(2×106.13-(2×2.0×2.0×0.8×24)/(2.0×2.0)))
=1/12×0.34^2×((2×2.0+2.0)*(2×106.13-(2×2.0×2.0×0.8×24)/(2.0×2.0)))
=1/12×0.34^2×(6*(2×106.13-(2×2.0×2.0×0.8×24)/(2.0×2.0)))
=1/12×0.34^2×(6*(2×106.13-153.6/(2.0×2.0)))
=1/12×0.34^2×(6*(2×106.13-153.6/4))
=1/12×0.34^2×(6*173.86)
=1/12×0.34^2×1043.16
=1/12×0.1156×1043.16
=0.083333×0.1156×1043.16
=0.009633×1043.16
=10.04876 Answer:1/12×(0.34)^2×((2×2.0+2.0)*(2×106.13-(2×2.0×2.0×0.8×24)/(2.0×2.0)))=10.04876Your problem has not been solved here? Please take a look at the hot problems !