There are 1 questions in this calculation: for each question, the 4 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ 4th\ derivative\ of\ function\ 20({e}^{{x}^{2}})\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 20{e}^{x^{2}}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 20{e}^{x^{2}}\right)}{dx}\\=&20({e}^{x^{2}}((2x)ln(e) + \frac{(x^{2})(0)}{(e)}))\\=&40x{e}^{x^{2}}\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( 40x{e}^{x^{2}}\right)}{dx}\\=&40{e}^{x^{2}} + 40x({e}^{x^{2}}((2x)ln(e) + \frac{(x^{2})(0)}{(e)}))\\=&40{e}^{x^{2}} + 80x^{2}{e}^{x^{2}}\\\\ &\color{blue}{The\ third\ derivative\ of\ function:} \\&\frac{d\left( 40{e}^{x^{2}} + 80x^{2}{e}^{x^{2}}\right)}{dx}\\=&40({e}^{x^{2}}((2x)ln(e) + \frac{(x^{2})(0)}{(e)})) + 80*2x{e}^{x^{2}} + 80x^{2}({e}^{x^{2}}((2x)ln(e) + \frac{(x^{2})(0)}{(e)}))\\=&240x{e}^{x^{2}} + 160x^{3}{e}^{x^{2}}\\\\ &\color{blue}{The\ 4th\ derivative\ of\ function:} \\&\frac{d\left( 240x{e}^{x^{2}} + 160x^{3}{e}^{x^{2}}\right)}{dx}\\=&240{e}^{x^{2}} + 240x({e}^{x^{2}}((2x)ln(e) + \frac{(x^{2})(0)}{(e)})) + 160*3x^{2}{e}^{x^{2}} + 160x^{3}({e}^{x^{2}}((2x)ln(e) + \frac{(x^{2})(0)}{(e)}))\\=&240{e}^{x^{2}} + 960x^{2}{e}^{x^{2}} + 320x^{4}{e}^{x^{2}}\\ \end{split}\end{equation} \]

Your problem has not been solved here? Please take a look at the  hot problems ！