Mathematics
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current location:Derivative function > Derivative function calculation history > Answer
    There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ {x}^{2}sin(x)tan(x)\ with\ respect\ to\ x:\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = x^{2}sin(x)tan(x)\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( x^{2}sin(x)tan(x)\right)}{dx}\\=&2xsin(x)tan(x) + x^{2}cos(x)tan(x) + x^{2}sin(x)sec^{2}(x)(1)\\=&2xsin(x)tan(x) + x^{2}cos(x)tan(x) + x^{2}sin(x)sec^{2}(x)\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( 2xsin(x)tan(x) + x^{2}cos(x)tan(x) + x^{2}sin(x)sec^{2}(x)\right)}{dx}\\=&2sin(x)tan(x) + 2xcos(x)tan(x) + 2xsin(x)sec^{2}(x)(1) + 2xcos(x)tan(x) + x^{2}*-sin(x)tan(x) + x^{2}cos(x)sec^{2}(x)(1) + 2xsin(x)sec^{2}(x) + x^{2}cos(x)sec^{2}(x) + x^{2}sin(x)*2sec^{2}(x)tan(x)\\=&2sin(x)tan(x) + 4xcos(x)tan(x) + 4xsin(x)sec^{2}(x) + 2x^{2}sin(x)tan(x)sec^{2}(x) + 2x^{2}cos(x)sec^{2}(x) - x^{2}sin(x)tan(x)\\ \end{split}\end{equation} \]





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