There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ \frac{ln({x}^{2} + 1)}{sin(x)}\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{ln(x^{2} + 1)}{sin(x)}\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( \frac{ln(x^{2} + 1)}{sin(x)}\right)}{dx}\\=&\frac{(2x + 0)}{(x^{2} + 1)sin(x)} + \frac{ln(x^{2} + 1)*-cos(x)}{sin^{2}(x)}\\=&\frac{2x}{(x^{2} + 1)sin(x)} - \frac{ln(x^{2} + 1)cos(x)}{sin^{2}(x)}\\ \end{split}\end{equation} \]Your problem has not been solved here? Please take a look at the hot problems !