There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ {-10}^{-5}{x}^{3} + 0.0009{x}^{2} - 0.0196x + 0.2531\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = -0.00001x^{3} + 0.0009x^{2} - 0.0196x + 0.2531\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( -0.00001x^{3} + 0.0009x^{2} - 0.0196x + 0.2531\right)}{dx}\\=&-0.00001*3x^{2} + 0.0009*2x - 0.0196 + 0\\=&-0.00003x^{2} + 0.0018x - 0.0196\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( -0.00003x^{2} + 0.0018x - 0.0196\right)}{dx}\\=&-0.00003*2x + 0.0018 + 0\\=&-0.00006x + 0.0018\\ \end{split}\end{equation} \]Your problem has not been solved here? Please take a look at the hot problems !