There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ {\frac{1}{(sin(x))}}^{2}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{1}{sin^{2}(x)}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( \frac{1}{sin^{2}(x)}\right)}{dx}\\=&\frac{-2cos(x)}{sin^{3}(x)}\\=&\frac{-2cos(x)}{sin^{3}(x)}\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( \frac{-2cos(x)}{sin^{3}(x)}\right)}{dx}\\=&\frac{-2*-3cos(x)cos(x)}{sin^{4}(x)} - \frac{2*-sin(x)}{sin^{3}(x)}\\=&\frac{6cos^{2}(x)}{sin^{4}(x)} + \frac{2}{sin^{2}(x)}\\ \end{split}\end{equation} \]

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