There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ 0.00001{x}^{3} - 0.0009{x}^{2} + 0.024x + 22.596\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 0.00001x^{3} - 0.0009x^{2} + 0.024x + 22.596\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 0.00001x^{3} - 0.0009x^{2} + 0.024x + 22.596\right)}{dx}\\=&0.00001*3x^{2} - 0.0009*2x + 0.024 + 0\\=&0.00003x^{2} - 0.0018x + 0.024\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( 0.00003x^{2} - 0.0018x + 0.024\right)}{dx}\\=&0.00003*2x - 0.0018 + 0\\=&0.00006x - 0.0018\\ \end{split}\end{equation} \]

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