There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ -0.00006{x}^{3} + 0.0005{x}^{2} + 0.0094x + 22.191\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = -0.00006x^{3} + 0.0005x^{2} + 0.0094x + 22.191\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( -0.00006x^{3} + 0.0005x^{2} + 0.0094x + 22.191\right)}{dx}\\=&-0.00006*3x^{2} + 0.0005*2x + 0.0094 + 0\\=&-0.00018x^{2} + 0.001x + 0.0094\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( -0.00018x^{2} + 0.001x + 0.0094\right)}{dx}\\=&-0.00018*2x + 0.001 + 0\\=&-0.00036x + 0.001\\ \end{split}\end{equation} \]

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