There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ (sin(2x - \frac{π}{6}))\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = sin(2x - \frac{1}{6}π)\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( sin(2x - \frac{1}{6}π)\right)}{dx}\\=&cos(2x - \frac{1}{6}π)(2 + 0)\\=&2cos(2x - \frac{1}{6}π)\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( 2cos(2x - \frac{1}{6}π)\right)}{dx}\\=&2*-sin(2x - \frac{1}{6}π)(2 + 0)\\=&-4sin(2x - \frac{1}{6}π)\\ \end{split}\end{equation} \]

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