There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ 0.0012{x}^{3} - 0.0246{x}^{2} + 0.3129x + 36.305\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 0.0012x^{3} - 0.0246x^{2} + 0.3129x + 36.305\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 0.0012x^{3} - 0.0246x^{2} + 0.3129x + 36.305\right)}{dx}\\=&0.0012*3x^{2} - 0.0246*2x + 0.3129 + 0\\=&0.0036x^{2} - 0.0492x + 0.3129\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( 0.0036x^{2} - 0.0492x + 0.3129\right)}{dx}\\=&0.0036*2x - 0.0492 + 0\\=&0.0072x - 0.0492\\ \end{split}\end{equation} \]

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