There are 1 questions in this calculation: for each question, the 4 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ 4th\ derivative\ of\ function\ sin({x}^{2})\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = sin(x^{2})\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( sin(x^{2})\right)}{dx}\\=&cos(x^{2})*2x\\=&2xcos(x^{2})\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( 2xcos(x^{2})\right)}{dx}\\=&2cos(x^{2}) + 2x*-sin(x^{2})*2x\\=&2cos(x^{2}) - 4x^{2}sin(x^{2})\\\\ &\color{blue}{The\ third\ derivative\ of\ function:} \\&\frac{d\left( 2cos(x^{2}) - 4x^{2}sin(x^{2})\right)}{dx}\\=&2*-sin(x^{2})*2x - 4*2xsin(x^{2}) - 4x^{2}cos(x^{2})*2x\\=&-12xsin(x^{2}) - 8x^{3}cos(x^{2})\\\\ &\color{blue}{The\ 4th\ derivative\ of\ function:} \\&\frac{d\left( -12xsin(x^{2}) - 8x^{3}cos(x^{2})\right)}{dx}\\=&-12sin(x^{2}) - 12xcos(x^{2})*2x - 8*3x^{2}cos(x^{2}) - 8x^{3}*-sin(x^{2})*2x\\=&-12sin(x^{2}) - 48x^{2}cos(x^{2}) + 16x^{4}sin(x^{2})\\ \end{split}\end{equation} \]

Your problem has not been solved here? Please take a look at the  hot problems ！