Mathematics
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current location:Derivative function > Derivative function calculation history > Answer
    There are 1 questions in this calculation: for each question, the 1 derivative of d is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ \frac{(o + p + q)({a}^{2} + {b}^{2})}{2} + \frac{r(h + i + j - 2hjsin(d))}{2}\ with\ respect\ to\ d:\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{1}{2}oa^{2} + \frac{1}{2}ob^{2} + \frac{1}{2}pa^{2} + \frac{1}{2}pb^{2} + \frac{1}{2}qa^{2} + \frac{1}{2}qb^{2} - rhjsin(d) + \frac{1}{2}ri + \frac{1}{2}rj + \frac{1}{2}rh\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( \frac{1}{2}oa^{2} + \frac{1}{2}ob^{2} + \frac{1}{2}pa^{2} + \frac{1}{2}pb^{2} + \frac{1}{2}qa^{2} + \frac{1}{2}qb^{2} - rhjsin(d) + \frac{1}{2}ri + \frac{1}{2}rj + \frac{1}{2}rh\right)}{dd}\\=&0 + 0 + 0 + 0 + 0 + 0 - rhjcos(d) + 0 + 0 + 0\\=& - rhjcos(d)\\ \end{split}\end{equation} \]





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