There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ (x - sin(x)){\frac{1}{x}}^{3}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = - \frac{sin(x)}{x^{3}} + \frac{1}{x^{2}}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( - \frac{sin(x)}{x^{3}} + \frac{1}{x^{2}}\right)}{dx}\\=& - \frac{-3sin(x)}{x^{4}} - \frac{cos(x)}{x^{3}} + \frac{-2}{x^{3}}\\=&\frac{3sin(x)}{x^{4}} - \frac{cos(x)}{x^{3}} - \frac{2}{x^{3}}\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( \frac{3sin(x)}{x^{4}} - \frac{cos(x)}{x^{3}} - \frac{2}{x^{3}}\right)}{dx}\\=&\frac{3*-4sin(x)}{x^{5}} + \frac{3cos(x)}{x^{4}} - \frac{-3cos(x)}{x^{4}} - \frac{-sin(x)}{x^{3}} - \frac{2*-3}{x^{4}}\\=& - \frac{12sin(x)}{x^{5}} + \frac{6cos(x)}{x^{4}} + \frac{sin(x)}{x^{3}} + \frac{6}{x^{4}}\\ \end{split}\end{equation} \]

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