There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ (xx + 2yz)(yy + 2zx)(zz + 2xy) - (xx + yy)(yy + zz)(zz + xx)\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 2y^{3}x^{3} + 2z^{3}x^{3} + 4yzx^{4} + 4y^{4}zx + 4yz^{4}x + 7y^{2}z^{2}x^{2} + 2y^{3}z^{3} - y^{2}x^{4} - z^{4}x^{2} - z^{2}x^{4} - y^{4}z^{2} - y^{4}x^{2} - y^{2}z^{4}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 2y^{3}x^{3} + 2z^{3}x^{3} + 4yzx^{4} + 4y^{4}zx + 4yz^{4}x + 7y^{2}z^{2}x^{2} + 2y^{3}z^{3} - y^{2}x^{4} - z^{4}x^{2} - z^{2}x^{4} - y^{4}z^{2} - y^{4}x^{2} - y^{2}z^{4}\right)}{dx}\\=&2y^{3}*3x^{2} + 2z^{3}*3x^{2} + 4yz*4x^{3} + 4y^{4}z + 4yz^{4} + 7y^{2}z^{2}*2x + 0 - y^{2}*4x^{3} - z^{4}*2x - z^{2}*4x^{3} + 0 - y^{4}*2x + 0\\=&6y^{3}x^{2} + 6z^{3}x^{2} + 16yzx^{3} + 14y^{2}z^{2}x + 4yz^{4} + 4y^{4}z - 4y^{2}x^{3} - 2z^{4}x - 4z^{2}x^{3} - 2y^{4}x\\ \end{split}\end{equation} \]

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