There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ -{e}^{x} - sin(x) + 2x + 1\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( -{e}^{x} - sin(x) + 2x + 1\right)}{dx}\\=&-({e}^{x}((1)ln(e) + \frac{(x)(0)}{(e)})) - cos(x) + 2 + 0\\=&-{e}^{x} - cos(x) + 2\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( -{e}^{x} - cos(x) + 2\right)}{dx}\\=&-({e}^{x}((1)ln(e) + \frac{(x)(0)}{(e)})) - -sin(x) + 0\\=&-{e}^{x} + sin(x)\\ \end{split}\end{equation} \]

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