There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ \frac{cos(5x + 7)}{sin(2 - 3x)}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{cos(5x + 7)}{sin(-3x + 2)}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( \frac{cos(5x + 7)}{sin(-3x + 2)}\right)}{dx}\\=&\frac{-cos(-3x + 2)(-3 + 0)cos(5x + 7)}{sin^{2}(-3x + 2)} + \frac{-sin(5x + 7)(5 + 0)}{sin(-3x + 2)}\\=&\frac{3cos(-3x + 2)cos(5x + 7)}{sin^{2}(-3x + 2)} - \frac{5sin(5x + 7)}{sin(-3x + 2)}\\ \end{split}\end{equation} \]

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