There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ aln(\frac{bx}{(bx + c)})\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = aln(\frac{bx}{(bx + c)})\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( aln(\frac{bx}{(bx + c)})\right)}{dx}\\=&\frac{a((\frac{-(b + 0)}{(bx + c)^{2}})bx + \frac{b}{(bx + c)})}{(\frac{bx}{(bx + c)})}\\=&\frac{-ab}{(bx + c)} + \frac{a}{x}\\ \end{split}\end{equation} \]Your problem has not been solved here? Please take a look at the hot problems !