There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ cos(3x - 4) + ln(-3x + 4)\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( cos(3x - 4) + ln(-3x + 4)\right)}{dx}\\=&-sin(3x - 4)(3 + 0) + \frac{(-3 + 0)}{(-3x + 4)}\\=&-3sin(3x - 4) - \frac{3}{(-3x + 4)}\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( -3sin(3x - 4) - \frac{3}{(-3x + 4)}\right)}{dx}\\=&-3cos(3x - 4)(3 + 0) - 3(\frac{-(-3 + 0)}{(-3x + 4)^{2}})\\=&-9cos(3x - 4) - \frac{9}{(-3x + 4)^{2}}\\ \end{split}\end{equation} \]Your problem has not been solved here? Please take a look at the hot problems !