There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ {ln(1 + x)}^{\frac{1}{x}}\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = {ln(x + 1)}^{\frac{1}{x}}\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( {ln(x + 1)}^{\frac{1}{x}}\right)}{dx}\\=&({ln(x + 1)}^{\frac{1}{x}}((\frac{-1}{x^{2}})ln(ln(x + 1)) + \frac{(\frac{1}{x})(\frac{(1 + 0)}{(x + 1)})}{(ln(x + 1))}))\\=&\frac{-{ln(x + 1)}^{\frac{1}{x}}ln(ln(x + 1))}{x^{2}} + \frac{{ln(x + 1)}^{\frac{1}{x}}}{(x + 1)xln(x + 1)}\\ \end{split}\end{equation} \]Your problem has not been solved here? Please take a look at the hot problems !