There are 1 questions in this calculation: for each question, the 3 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ third\ derivative\ of\ function\ {(3{x}^{2} + 1)}^{3}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 27x^{6} + 27x^{4} + 9x^{2} + 1\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 27x^{6} + 27x^{4} + 9x^{2} + 1\right)}{dx}\\=&27*6x^{5} + 27*4x^{3} + 9*2x + 0\\=&162x^{5} + 108x^{3} + 18x\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( 162x^{5} + 108x^{3} + 18x\right)}{dx}\\=&162*5x^{4} + 108*3x^{2} + 18\\=&810x^{4} + 324x^{2} + 18\\\\ &\color{blue}{The\ third\ derivative\ of\ function:} \\&\frac{d\left( 810x^{4} + 324x^{2} + 18\right)}{dx}\\=&810*4x^{3} + 324*2x + 0\\=&3240x^{3} + 648x\\ \end{split}\end{equation} \]

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