There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ \frac{(2cos(2)x)}{(4 + sin(2)x)}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{2xcos(2)}{(xsin(2) + 4)}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( \frac{2xcos(2)}{(xsin(2) + 4)}\right)}{dx}\\=&2(\frac{-(sin(2) + xcos(2)*0 + 0)}{(xsin(2) + 4)^{2}})xcos(2) + \frac{2cos(2)}{(xsin(2) + 4)} + \frac{2x*-sin(2)*0}{(xsin(2) + 4)}\\=&\frac{-2xsin(2)cos(2)}{(xsin(2) + 4)^{2}} + \frac{2cos(2)}{(xsin(2) + 4)}\\ \end{split}\end{equation} \]

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