There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ 4cos(2sin(2)x)cos(2)x\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 4xcos(2)cos(2xsin(2))\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 4xcos(2)cos(2xsin(2))\right)}{dx}\\=&4cos(2)cos(2xsin(2)) + 4x*-sin(2)*0cos(2xsin(2)) + 4xcos(2)*-sin(2xsin(2))(2sin(2) + 2xcos(2)*0)\\=&4cos(2)cos(2xsin(2)) - 8xsin(2xsin(2))sin(2)cos(2)\\ \end{split}\end{equation} \]

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