There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ 2e^{-2x} + 4xe^{-2x}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 2e^{-2x} + 4xe^{-2x}\right)}{dx}\\=&2e^{-2x}*-2 + 4e^{-2x} + 4xe^{-2x}*-2\\=& - 8xe^{-2x}\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( - 8xe^{-2x}\right)}{dx}\\=& - 8e^{-2x} - 8xe^{-2x}*-2\\=& - 8e^{-2x} + 16xe^{-2x}\\ \end{split}\end{equation} \]

Your problem has not been solved here? Please take a look at the  hot problems ！