Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation （x+3)(x+2)(4-x)+3+x+16-4x = 0 .
    Question type: Equation
    Solution:Original question:

(

x

+

3

)

(

x

+

2

)

(

4

−

x

)

+

3

+

x

+

16

−

4

x

=

0

Left side of the equation =

(

x

+

3

)

(

x

+

2

)

(

4

−

x

)

+

19

−

3

x

    The equation is transformed into :

(

x

+

3

)

(

x

+

2

)

(

4

−

x

)

+

19

−

3

x

=

0

    Remove the bracket on the left of the equation:

Left side of the equation =

x

(

x

+

2

)

(

4

−

x

)

+

3

(

x

+

2

)

(

4

−

x

)

+

19

−

3

x

=

x

x

(

4

−

x

)

+

x

×

2

(

4

−

x

)

+

3

(

x

+

2

)

(

4

−

x

)

+

19

−

3

x

=

x

x

×

4

−

x

x

x

+

x

×

2

(

4

−

x

)

+

3

(

x

+

2

)

(

4

−

x

)

=

x

x

×

4

−

x

x

x

+

x

×

2

×

4

−

x

×

2

x

=

x

x

×

4

−

x

x

x

+

x

×

8

−

x

×

2

x

+

3

=

x

x

×

4

−

x

x

x

+

5

x

−

x

×

2

x

+

3

=

x

x

×

4

−

x

x

x

+

5

x

−

x

×

2

x

+

3

=

x

x

×

4

−

x

x

x

+

5

x

−

x

×

2

x

+

3

=

x

x

×

4

−

x

x

x

+

5

x

−

x

×

2

x

+

3

=

x

x

×

4

−

x

x

x

+

5

x

−

x

×

2

x

+

12

=

x

x

×

4

−

x

x

x

+

17

x

−

x

×

2

x

−

3

=

x

x

×

4

−

x

x

x

+

17

x

−

x

×

2

x

−

3

=

x

x

×

4

−

x

x

x

+

17

x

−

x

×

2

x

−

3

=

x

x

×

4

−

x

x

x

+

11

x

−

x

×

2

x

−

3

    The equation is transformed into :

x

x

×

4

−

x

x

x

+

11

x

−

x

×

2

x

−

3

=

0

    
        x≈4.149063 , keep 6 decimal places    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》

Your problem has not been solved here? Please take a look at the  hot problems ！