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current location:Mathematical operation > History of Inequality Computation > Answer
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[ 1/1 Equation]
    Work: Find the solution of equation 3*(N*129*0.2+400) = N*129*0.8-400 .
    Question type: Equation
    Solution:Original question:
     3( N × 129 ×
1
5
+ 400) = N × 129 ×
4
5
400
    Remove the bracket on the left of the equation:
     Left side of the equation = 3 N × 129 ×
1
5
+ 3 × 400
                                             =
387
5
N + 1200
    The equation is transformed into :
     
387
5
N + 1200 = N × 129 ×
4
5
400
     Right side of the equation = N ×
516
5
400
    The equation is transformed into :
     
387
5
N + 1200 =
516
5
N 400

    Transposition :
     
387
5
N
516
5
N = - 4001200

    Combine the items on the left of the equation:
      -
129
5
N = - 4001200

    Combine the items on the right of the equation:
      -
129
5
N = - 1600

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     1600 =
129
5
N

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
129
5
N = 1600

    The coefficient of the unknown number is reduced to 1 :
      N = 1600 ÷
129
5
        = 1600 ×
5
129

    We obtained :
      N =
8000
129
    This is the solution of the equation.

    Convert the result to decimal form :
      N = 62.015504




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