Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality -4000-1000/(1+x)+600(1-(1+x)^29)/（1-x）(1+x)^2 <0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
        -4000 - 1000 / ( 1 + x ) + 600 * ( 1 - ( 1 + x ) ^ 29 ) / ( 1 - x ) * ( 1 + x ) ^ 2 <0         (1)
        From the definition field of divisor
         1 + x ≠ 0        (2 )
        From the definition field of divisor
         1 - x ≠ 0        (3 )

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    From inequality(1)：
         -2.090553 < x < -1.251054 或  -1 < x < 1
    From inequality(2)：
         x < -1 或  x ＞ -1
    From inequality(3)：
         x < 1 或  x ＞ 1

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    From inequalities (1) and (2)
         -2.090553 < x < -1.251054 或  -1 < x < 1     (4)
    From inequalities (3) and (4)
         -2.090553 < x < -1.251054 或  -1 < x < 1     (5)

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    The final solution set is :
         -2.090553 < x < -1.251054 或  -1 < x < 1

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