Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1+2d)^(2) = (1+d)×(1+5d) .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, it is converted into:
    ( d + 2 )( d - 0 )=0
    From
        d + 2 = 0
        d - 0 = 0
    it is concluded that:：
        d₁=-2
        d₂=0    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》

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